If E Is Considered To Be A Continuously Divisible Quantity, This Distribution Is Possible In Infinitely Many Ways. We Consider, However-this Is The Most Essential Point Of The Whole Calculation-e To Be Composed Of A Well-defined Number Of Equal Parts And Use Thereto The Constant Of Nature H = 6.55 ×10-27 Erg Sec. This Constant Multiplied By The Common Frequency ? Of The Resonators Gives Us The Energy Element E In Erg, And Dividing E By E We Get The Number P Of Energy Elements Which Must Be Divided Over The N Resonators.
Please Wait....
Translating....
Translating....
If E Is Considered To Be A
Max Planck
If E Is Considered To Be A Continuously Divisible Quantity, This Distribution Is Possible In Infinitely Many Ways. We Consider, However-this Is The Most Essential Point Of The Whole Calculation-e To Be Composed Of A Well-defined Number Of Equal Parts And Use Thereto The Constant Of Nature H = 6.55 ×10-27 Erg Sec. This Constant Multiplied By The Common Frequency ? Of The Resonators Gives Us The Energy Element E In Erg, And Dividing E By E We Get The Number P Of Energy Elements Which Must Be Divided Over The N Resonators.
Views: 19
